How do I define an integer constant in binary format?

The JDK 7 add a small feature to work with a binary number. In the previous JDK we have to use the Integer.parseInt() method if we need to work with other base number. But with this new feature introduced in the Project Coin we can simplify the code when we work with the binary number.

To specify a binary literal in the code, add the prefix 0b or 0B to the number. The following code snippet show you how to write the binary literals:

package org.kodejava.basic;

public class BinaryLiteralExample {
    public static void main(String[] args) {
        // In JDK 6 and the previous version you must use the
        // Integer.parseInt() method to define a number using
        // a binary literal.
        int x = Integer.parseInt("00101010", 2);
        System.out.println("x = " + x);

        // In the new JDK 7 you can simply use the following
        // binary literal to define a number using a binary
        // literal.
        int y = 0b00101010;
        System.out.println("y = " + y);
    }
}

The result of our code snippet:

x = 42
y = 42

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Wayan

Founder at Kode Java

A programmer, runner and recreational diver, lives on the island of Bali, Indonesia. Programming in Java, Spring Framework, Hibernate / JPA, MySQL. To support me working on this project, buy me a cup of coffee, every little bit helps. Thank you.

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