How do I count the occurrences of a number in an array?

By Wayan in Basic, Core API 4 Comments 
package org.kodejava.basic;

import java.util.HashMap;
import java.util.Map;

public class NumberOccurrenceInArray {
    public static void main(String[] args) {
        int[] numbers = new int[]{1, 8, 3, 4, 3, 2, 5, 7, 3, 1, 4, 5, 6, 4, 3};

        Map<Integer, Integer> map = new HashMap<>();
        for (int key : numbers) {
            if (map.containsKey(key)) {
                int occurrence = map.get(key);
                occurrence++;
                map.put(key, occurrence);
            } else {
                map.put(key, 1);
            }
        }

        for (Integer key : map.keySet()) {
            int occurrence = map.get(key);
            System.out.println(key + " occur " + occurrence + " time(s).");
        }
    }
}

The result are:

1 occur 2 time(s).
2 occur 1 time(s).
3 occur 4 time(s).
4 occur 3 time(s).
5 occur 2 time(s).
6 occur 1 time(s).
7 occur 1 time(s).
8 occur 1 time(s).
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4 Comments

    • So I figured it out. The values in get key were null using a foreach loop I set it all to zero. I thought that since it was Integer, 0 would be default.

      Reply

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