How do I generate a random alphanumeric string?

By I Wayan Saryada in Apache Commons, Commons Lang 1 Comment

The code below show you how to use the Apache Commons-Lang RandomStringUtils class to generate some random string data.

package org.kodejava.commons.lang;

import org.apache.commons.lang3.RandomStringUtils;

public class RandomStringUtilsDemo {
    public static void main(String[] args) {
        // Creates a 64-chars length random string of number.
        String result = RandomStringUtils.random(64, false, true);
        System.out.println("random = " + result);

        // Creates a 64-chars length of random alphabetic string.
        result = RandomStringUtils.randomAlphabetic(64);
        System.out.println("random = " + result);

        // Creates a 32-chars length of random ascii string.
        result = RandomStringUtils.randomAscii(32);
        System.out.println("random = " + result);

        // Creates a 32-chars length of string from the defined array of
        // characters including numeric and alphabetic characters.
        result = RandomStringUtils.random(32, 0, 20, true, true,
                "qw32rfHIJk9iQ8Ud7h0X".toCharArray());
        System.out.println("random = " + result);
    }
}

The example of our program result are:

random = 6251115933802303614285104650603664973302700879175809706257640062
random = EbKuzxERdBtCCHtbRuYnLwfnirtIqkcwwHxvZofkaGLNsNblCaVoLXFxfjYjXSHk
random = v9cJK?=d-Jl b-pisn9vUGxCV1&*>StY
random = XirkhUHHfwUf3kih8Hw877882d9i8Q3q

Maven Dependencies

<dependency>
    <groupId>org.apache.commons</groupId>
    <artifactId>commons-lang3</artifactId>
    <version>3.14.0</version>
</dependency>

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How do I read a file into byte array using Apache Commons IO?

By I Wayan Saryada in Apache Commons, Commons IO 0 Comment

The following example shows you how to read file contents into byte array. We use the IOUtils class of the Apache Commons IO library.

package org.kodejava.commons.io;

import org.apache.commons.io.IOUtils;

import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;

public class FileToByteArray {
    public static void main(String[] args) {
        File file = new File("README.md");
        try {
            InputStream is = new FileInputStream(file);
            byte[] bytes = IOUtils.toByteArray(is);

            System.out.println("Byte array size: " + bytes.length);
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

Maven Dependencies

<dependency>
    <groupId>commons-io</groupId>
    <artifactId>commons-io</artifactId>
    <version>2.16.1</version>
</dependency>

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How do I get the content of an InputStream as a String?

By I Wayan Saryada in Apache Commons, Commons IO 0 Comment

We can use the code below to convert the content of an InputStream into a String. At first, we use FileInputStream create to a stream to a file that going to be read. IOUtils.toString(InputStream input, String encoding) method gets the content of the InputStream and returns a string representation of it.

package org.kodejava.commons.io;

import org.apache.commons.io.IOUtils;

import java.io.InputStream;
import java.io.FileInputStream;
import java.nio.charset.StandardCharsets;

public class InputStreamToString {
    public static void main(String[] args) throws Exception {
        // Create an input stream for reading data.txt file content.
        try (InputStream is = new FileInputStream("data.txt")) {
            // Get the content of an input stream as a string using UTF-8
            // as the character encoding.
            String contents = IOUtils.toString(is, StandardCharsets.UTF_8);
            System.out.println(contents);
        }
    }
}

Maven Dependencies

<dependency>
    <groupId>commons-io</groupId>
    <artifactId>commons-io</artifactId>
    <version>2.16.1</version>
</dependency>

Maven Central

How do I create a web based file upload?

By I Wayan Saryada in Apache Commons, Commons File Upload 0 Comment

This example using the Apache Commons FileUpload library to create a simple application for uploading files. The program is divided into two parts, a form using JSP and a servlet for handling the upload process. To run the sample you need to download the Commons FileUpload and Commons IO get the latest stable version.

Commons FileUpload Demo

Commons FileUpload Demo

The first step is to create the upload form. The form contains two fields for selecting file to be uploaded and a submit button. The form should have an enctype attribute and the value is multipart/form-data. We use a post method and the submit process is handled by the upload-servlet as defined in the action attribute.

<%@ page contentType="text/html;charset=UTF-8" %>
<!DOCTYPE html>
<html lang="en">
<head>
    <title>File Upload</title>
</head>

<body>
<h1>File Upload Form</h1>
<hr/>
<form action="${pageContext.request.contextPath}/upload-servlet"
      method="post" enctype="multipart/form-data">

    <fieldset>
        <legend>Upload File</legend>
        <label for="filename_1">File: </label>
        <input id="filename_1" type="file" name="filename_1" size="50"/><br/>
        <label for="filename_2">File: </label>
        <input id="filename_2" type="file" name="filename_2" size="50"/><br/>
        <br/>
        <input type="submit" value="Upload File"/>
    </fieldset>

</form>
</body>
</html>

The second step is to create the servlet. The doPost method checks to see if the request contains a multipart content. After that we create a FileItemFactory, in this example we use the DiskFileItemFactory which is the default factory for FileItem. This factory creates an instance of FileItem and stored it either in memory or in a temporary file on disk depending on its content size.

The ServletFileUpload handles multiple files upload that we’ve specified in the form above sent using the multipart/form-data encoding type. The process of storing the data is determined by the FileItemFactory passed to the ServletFileUpload class.

The next steps is to parse the multipart/form-data stream by calling the ServletFileUpload.parseRequest(HttpServletRequest request) method. The parse process return a list of FileItem. After that we iterate on the list and check to see if FileItem representing an uploaded file or a simple form field. If it is represents an uploaded file we write the FileItem content to a file.

So here is the FileUploadDemoServlet.

package org.kodejava.commons.fileupload;

import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.FileItemFactory;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.File;
import java.io.IOException;
import java.io.Serial;
import java.util.List;

@WebServlet(urlPatterns = "/upload-servlet")
public class FileUploadDemoServlet extends HttpServlet {
    @Serial
    private static final long serialVersionUID = 1L;

    protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        boolean isMultipart = ServletFileUpload.isMultipartContent(request);

        if (isMultipart) {
            FileItemFactory factory = new DiskFileItemFactory();
            ServletFileUpload upload = new ServletFileUpload(factory);

            try {
                List<FileItem> items = upload.parseRequest(request);
                for (FileItem item : items) {
                    if (!item.isFormField()) {
                        String fileName = item.getName();

                        String root = getServletContext().getRealPath("/");
                        File path = new File(root + "/uploads");
                        if (!path.exists()) {
                            boolean status = path.mkdirs();
                        }

                        File uploadedFile = new File(path + "/" + fileName);
                        System.out.println(uploadedFile.getAbsolutePath());
                        item.write(uploadedFile);
                    }
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
    }
}

Maven Dependencies

<dependencies>
    <dependency>
        <groupId>javax.servlet</groupId>
        <artifactId>javax.servlet-api</artifactId>
        <version>4.0.1</version>
    </dependency>
    <dependency>
        <groupId>commons-fileupload</groupId>
        <artifactId>commons-fileupload</artifactId>
        <version>1.5</version>
    </dependency>
</dependencies>

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How do I set mapped property value of a bean?

By I Wayan Saryada in Apache Commons, Commons Beanutils 0 Comment

This example demonstrate how to use PropertyUtils.setMappedProperty() method to modify a Map typed property value of a bean. To set the property we need to pass bean instance, property name, map key and map value to PropertyUtils.setMappedProperty() method.

package org.kodejava.commons.beanutils;

import org.apache.commons.beanutils.PropertyUtils;
import org.kodejava.commons.beanutils.support.Track;
import org.kodejava.commons.beanutils.support.Record;

import java.util.HashMap;
import java.util.Map;

public class PropertySetMappedExample {

    public static void main(String[] args) {
        // Create an instance of Recording bean.
        Record record = new Record();
        record.setId(1L);
        record.setTitle("Introduction");

        // Create a map to hold record tracks.
        Map<String, Track> tracks = new HashMap<>();
        tracks.put("track-one", new Track());
        tracks.put("track-two", new Track());
        tracks.put("track-three", new Track());
        record.setMapTracks(tracks);

        try {
            // We add another tracks to the record track using
            // a PropertyUtils.setMappedProperty() method.
            PropertyUtils.setMappedProperty(record,
                    "mapTracks", "track-four", new Track());
            PropertyUtils.setMappedProperty(record,
                    "mapTracks", "track-five", new Track());
        } catch (Exception e) {
            e.printStackTrace();
        }

        tracks = record.getMapTracks();
        System.out.println("New Track Numbers: " + tracks.size());
        for (String key : tracks.keySet()) {
            System.out.println(key + " = " + tracks.get(key));
        }
    }
}

Maven Dependencies

<dependency>
    <groupId>commons-beanutils</groupId>
    <artifactId>commons-beanutils</artifactId>
    <version>1.9.4</version>
</dependency>

Maven Central