How do I create a beep sound?

By Wayan in AWT, Core API 0 Comment 
package org.kodejava.awt;

import java.awt.*;

public class BeepExample {
    public static void main(String[] args) {
        // This is the way we can send a beep audio out.
        Toolkit.getDefaultToolkit().beep();
    }
}

Using Runtime.exec() method we can do something like the code snippet below to produce beep sound using powershell command.

try {
    Process process = Runtime.getRuntime().exec(
            new String[]{"powershell", "[console]::beep()"});

    int errorCode = process.waitFor();
    int exitValue = process.exitValue();
    System.out.println("errorCode = " + errorCode);
    System.out.println("exitValue = " + exitValue);
} catch (Exception e) {
    throw new RuntimeException(e);
}

We can also execute external command using ProcessBuilder class like the following code snippet:

try {
    ProcessBuilder processBuilder = new ProcessBuilder();
    processBuilder.command("powershell", "[console]::beep()");
    Process process = processBuilder.start();

    int errorCode = process.waitFor();
    int exitValue = process.exitValue();
    System.out.println("errorCode = " + errorCode);
    System.out.println("exitValue = " + exitValue);
} catch (Exception e) {
    throw new RuntimeException(e);
}

How do I sort an array of objects?

By Wayan in Core API, Util Package 0 Comment

In this example we are going to learn how to sort an array of objects. We start by using an array of String objects as can be seen in the code snippet below. We sort the contents of the array using Arrays.sort() method and print the sorted result. It was really simple.

String names[] = {"Bob", "Mallory", "Alice", "Carol"};
Arrays.sort(names);
System.out.println("Names = " + Arrays.toString(names));

Next, we will sort an array of our own object. It is a bit different compared to sorting an array of primitives. The first rule is we need our object to implements the Comparable interface. This interface have one contract we need to implement, the compareTo() contract.

The basic rule of the compareTo() method is to return 0 when objects value are equals, 1 if this object value is greater and -1 if this object value is smaller. In the Person class below we simply call the String object compareTo() method. See the Person class below for more details.

package org.kodejava.util.support;

public class Person implements Comparable<Person> {
    private String name;

    public Person(String name) {
        this.name = name;
    }

    public int compareTo(Person person) {
        return this.name.compareTo(person.name);
    }

    public String toString() {
        return name;
    }
}

In the snippet below we create four Person objects. We sort the Person object based on their name using the Arrays.sort() method and print out the array values.

Person persons[] = new Person[4];
persons[0] = new Person("Bob");
persons[1] = new Person("Mallory");
persons[2] = new Person("Alice");
persons[3] = new Person("Carol");
Arrays.sort(persons);
System.out.println("Persons = " + Arrays.toString(persons));

This is the main class where you can run all the snippet above:

package org.kodejava.util;

import org.kodejava.util.support.Person;

import java.util.Arrays;

public class ObjectSortExample {
    public static void main(String[] args) {
        String[] names = {"Bob", "Mallory", "Alice", "Carol"};
        Arrays.sort(names);
        System.out.println("Names = " + Arrays.toString(names));

        Person[] persons = new Person[4];
        persons[0] = new Person("Bob");
        persons[1] = new Person("Mallory");
        persons[2] = new Person("Alice");
        persons[3] = new Person("Carol");
        Arrays.sort(persons);
        System.out.println("Persons = " + Arrays.toString(persons));
    }
}

This snippet will print the following output:

Names = [Alice, Bob, Carol, Mallory]
Persons = [Alice, Bob, Carol, Mallory]

How do I search specific value in an array?

By Wayan in Core API, Util Package 0 Comment 
package org.kodejava.util;

import java.util.Arrays;

public class ArraySearchExample {
    public static void main(String[] args) {
        // We create an array of ints where the search will be done.
        int[] items = {9, 5, 14, 6, 11, 28, 9, 16, 37, 3, 2};

        // The Arrays.binarySearch() require us to sort the array
        // items before we call the method. We can utilize the
        // Arrays.sort() method to do this. If we did not sort the
        // array the result will be undefined, the search process
        // will return a negative result.
        Arrays.sort(items);

        // To search we use Arrays.binarySearch() methods which accept
        // parameters of any array type. To search we passed the array
        // to be searched and the key to be searched for.
        //
        // When the search item exist more than one in the array, this
        // method gives no guarantee which one will be returned.
        int needle = 9;
        int index = Arrays.binarySearch(items, needle);

        // Print out where the 9 number is located in the array.
        System.out.println("Items: " + Arrays.toString(items));
        System.out.println("Item " + needle + " is at index " + index);
    }
}

There result of the code snippet:

Items: [2, 3, 5, 6, 9, 9, 11, 14, 16, 28, 37]
Item 9 is at index 5

How do I sort elements of an array?

By Wayan in Core API, Util Package 0 Comment 
package org.kodejava.util;

import java.util.Arrays;

public class ArraySortExample {
    public static void main(String[] args) {
        // An array of random numbers
        int[] numbers = {3, 1, 8, 34, 1, 2, 13, 89, 5, 21, 55};
        System.out.println("Before: " + Arrays.toString(numbers));

        // We need to sort these array elements into a correct order
        // from the smallest to the greatest. We will use the Arrays
        // class on java.utils package to do the sort. The sort
        // method of this class are overloaded, so they can take
        // other type of array as well such as byte[], long[],
        // float[], Object[].
        Arrays.sort(numbers);
        System.out.println("After : " + Arrays.toString(numbers));

        // We can also do the sort only for the specified range of
        // array elements.
        float[] money = {1.05f, 99.8f, 3f, 4.55f, 7.23f, 6.50f};
        Arrays.sort(money, 3, money.length);

        // Here we display the sort result, the first and the second
        // element of the array is not included in the sort process.
        System.out.println("Money : " + Arrays.toString(money));
    }
}

And here are the results:

Before: [3, 1, 8, 34, 1, 2, 13, 89, 5, 21, 55]
After : [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
Money : [1.05, 99.8, 3.0, 4.55, 6.5, 7.23]

How do I check if a file exists?

By Wayan in Core API, IO 0 Comment

To check if a file, or a directory exists we can utilize java.io.File.exists() method. This method return either true or false. Before we can check whether its exists or not we need to create an instance of File that represent an abstract path name of the file or directory. After we have the File instance we can call the exists() method to validate it.

package org.kodejava.io;

import java.io.File;
import java.io.FileNotFoundException;

public class FileExists {
    public static void main(String[] args) throws Exception {
        // Create an abstract definition of configuration file to be
        // read.
        File file = new File("applicationContext-hibernate.xml");

        // Print the exact location of the file in file system.
        System.out.println("File = " + file.getAbsolutePath());

        // If configuration file, applicationContext-hibernate.xml
        // does not exist in the current path throws an exception.
        if (!file.exists()) {
            String message = "Cannot find configuration file!";
            System.out.println(message);
            throw new FileNotFoundException(message);
        }

        // Continue with application logic here!
    }
}