How do I know if a character is uppercase?

By I Wayan Saryada in Core API, Lang Package 0 Comment

In the previous example How do I know if a character is lowercase?, we’ve learned how to use the Character.isLowerCase() method. Now we will learn how to use the other method, which is the Character.isUpperCase() to determine if a letter is in an uppercase form. This method also return a boolean value that indicates whether the character is in uppercase form or not.

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Another way to check if a letter is in uppercase form is by comparing the type of the characters, that can be obtained using the Character.getType() method with a defined constant value Character.UPPERCASE_LETTER.

Below is the code snippet that demonstrate these methods.

package org.kodejava.example.lang;

public class CharacterIsUpperCaseExample {
    public static void main(String[] args) {
        char a = 'A';

        // Checks to see if a letter is a uppercase letter.
        if (Character.isUpperCase(a)) {
            System.out.println(a + " is an uppercase character.");
        }

        // Checks to see if a letter is an uppercase letter
        // by comparing the character type against
        // Character.UPPERCASE_LETTER constant value.
        int charType = Character.getType(a);
        if (charType == Character.UPPERCASE_LETTER) {
            System.out.println(a + " is an uppercase character.");
        }
    }
}

The above example give you the following result when it executed:

A is an uppercase character.
A is an uppercase character.

How do I know if a character is lowercase?

By I Wayan Saryada in Core API, Lang Package 0 Comment

In this example you are going to learn another example on using the java.lang.Character class. The Character.isLowerCase() method can be used to determine if a letter is a lowercase letter. This method takes a char as argument and return a boolean value. If it returns true it means the character is in lowercase form. And if it returns false it means the character is not in lowercase form.

Beside using the isLowerCase() method you can also compare the character type with the constant value of Character.LOWERCASE_LETTER. To get the character type you can use the Character.getType() method. You can see the example on the following code snippet.

package org.kodejava.lang;

public class CharacterIsLowerCaseExample {
    public static void main(String[] args) {
        char a = 'a';

        // Checks to see if a letter is a lowercase letter.
        if (Character.isLowerCase(a)) {
            System.out.println(a + " is a lowercase letter.");
        }

        // Checks to see if a letter is a lowercase letter
        // by comparing the character type against
        // Character.LOWERCASE_LETTER constant value.
        int charType = Character.getType(a);
        if (charType == Character.LOWERCASE_LETTER) {
            System.out.println(a + " is a lowercase letter.");
        }
    }
}

This example give you the following output:

a is a lowercase letter.
a is a lowercase letter.

How do I check if a character representing an alphabet?

By I Wayan Saryada in Core API, Lang Package 2 Comments

In the previous example you’ve learned how to use the Character.isDigit() method to check if a character representing a digit.

In this example you will learn how to check if a character representing a letter. You can use the Character.isLetter(char c) method to check if a character is a valid letter. This method will return a true value for a valid letter characters and false if the character is not a valid letter.

In the code snippet below you will also learn how to use the toCharArray() method to covert a string into an array of char. Here we use the method so that we can check every character in the for-each loop to see is the character is a letter or not.

package org.kodejava.lang;

public class CharacterIsLetterExample {
    public static void main(String[] args) {
        String name = "Kode Java 123";

        // Determines if the specified character is a letter
        if (Character.isLetter(name.charAt(5))) {
            System.out.println("The fifth character (" +
                    name.charAt(5) + ") is an alphabet!");
        }

        // Iterates all characters in the string to see if it is
        // a letter or not.
        for (char c : name.toCharArray()) {
            if (Character.isLetter(c)) {
                System.out.println(c + " is a letter.");
            } else {
                System.out.println(c + " not a letter.");
            }
        }
    }
}

The code will print the following output:

The fifth character (J) is an alphabet!
K is a letter.
o is a letter.
d is a letter.
e is a letter.
  not a letter.
J is a letter.
a is a letter.
v is a letter.
a is a letter.
  not a letter.
1 not a letter.
2 not a letter.
3 not a letter.

How do I check if a character representing a number?

By I Wayan Saryada in Core API, Lang Package 0 Comment

For validation purposes we might need to check if data entered by our users is a valid data for our application to process. A simple mechanism for checking if a character inputted is a digit or not can be done by using the java.lang.Character class isDigit(char c) method.

In this example you will learn how to check if a character representing a number. You will start by creating a string that contains some random alphanumeric characters in it. And then you are going to iterate these characters, get the value at the specific location using the charAt() method. In the last section you are going to check to if the character represent a digit or not.

package org.kodejava.lang;

public class CharacterIsDigitExample {
    public static void main(String[] args) {
        // Manually creates a string with randoms characters.
        String str = "12?XYZ4!6cba78+HI@0";

        for (int i = 0; i < str.length(); i++) {
            // Determines if the specified character is a digit
            if (Character.isDigit(str.charAt(i))) {
                System.out.println(str.charAt(i) + " is a digit.");
            } else {
                System.out.println(str.charAt(i) + " not a digit.");
            }
        }
    }
}

These are the outputs of our program:

1 is a digit.
2 is a digit.
? not a digit.
X not a digit.
Y not a digit.
Z not a digit.
4 is a digit.
! not a digit.
6 is a digit.
c not a digit.
b not a digit.
a not a digit.
7 is a digit.
8 is a digit.
+ not a digit.
H not a digit.
I not a digit.
@ not a digit.
0 is a digit.

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How do I know if an ArrayList contains a specified item?

By I Wayan Saryada in Core API, Util Package 2 Comments

In this example we are going to learn how to find out if an ArrayList object contains the specified element. To check if an ArrayList object contains the specified element we can use the contains(Object o) method. This method returns a boolean true when the specified element is found in the ArrayList, otherwise return false. The method returns true if and only if the list contains at least one element, where the element equals to the item in the list.

Let’s see the code snippet below to demonstrate it.

package org.kodejava.util;

import java.util.ArrayList;
import java.util.List;

public class ArrayListContainsExample {
    public static void main(String[] args) {
        List<String> list = new ArrayList<>();
        list.add("Item 1");
        list.add("Item 2");
        list.add("Item 3");
        list.add("Item 4");

        // Check to see if the list contains "Item 1".
        String itemToFind = "Item 1";
        System.out.println("contains(" + itemToFind + "): " + list.contains(itemToFind));

        // Check to see if the list contains "Item 20".
        itemToFind = "Item 20";
        System.out.println("contains(" + itemToFind + "): " + list.contains(itemToFind));
    }
}

The output of the code snippet above are:

contains(Item 1): true
contains(Item 20): false