To use Files.probeContentType(Path path) in Java, you simply pass a Path object to the method. It returns a string representing the MIME type (e.g., image/png, text/plain) or null if the type cannot be determined.

Here is a practical example of how to implement it:

package org.kodejava.nio;

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;

public class ProbeContentTypeExample {
    public static void main(String[] args) {
        // Paths to different types of files
        Path imagePath = Paths.get("logo.png");
        Path textPath = Paths.get("example.txt");
        Path htmlPath = Paths.get("google.html");

        try {
            // Detect and print the content types
            System.out.println("Logo type: " + Files.probeContentType(imagePath));
            System.out.println("Text type: " + Files.probeContentType(textPath));
            System.out.println("HTML type: " + Files.probeContentType(htmlPath));
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

Key points to remember:

• Implementation-Dependent: The detection mechanism depends on the installed FileTypeDetector implementations and the underlying operating system. On Windows, it usually checks the registry based on the file extension.
• Returns Null: If the system cannot determine the file type, it returns null rather than throwing an exception.
• IOException: While rare for this specific method, it can throw an IOException if an I/O error occurs.
• No Content Inspection: By default, Files.probeContentType usually relies on file extensions and metadata rather than reading the actual byte content of the file. If you need deep content inspection (magic bytes), you might need a library like Apache Tika.