How to get some information about Path object?

By Wayan in Core API, IO 0 Comment

The java.nio.Path provides some methods to obtain information about the Path. For example, you can get information about the file name, the parent and the root path. For these you can call the getFileName(), getParent() and getRoot() method respectively.

You can also get the number of elements that make up this Path using the getNameCount() method. And to get the sub-path you can use the subpath() method and specify the starting and ending indexes. The code snippet below demonstrate to you how to get this information.

package org.kodejava.io;

import java.nio.file.Path;
import java.nio.file.Paths;

public class PathInfoExample {
    public static void main(String[] args) {
        // Create a Path for Windows notepad program.
        Path notepad = Paths.get("C:/Windows/System32/notepad.exe");

        // Get some information about the Path object.
        System.out.printf("File name         : %1$s%n", notepad.getFileName());
        System.out.printf("Name count        : %1$s%n", notepad.getNameCount());
        System.out.printf("Parent path       : %1$s%n", notepad.getParent());
        System.out.printf("Root path         : %1$s%n", notepad.getRoot());
        System.out.printf("Sub path from root: %1$s%n", notepad.subpath(0, 2));
    }
}

This code will print something like:

File name         : notepad.exe
Name count        : 3
Parent path       : C:\Windows\System32
Root path         : C:\
Sub path from root: Windows\System32

How do I create a java.nio.Path?

By Wayan in Core API, IO 0 Comment

The following code snippet show you how to create a Path. A Path (java.nio.Path) in an interface that represent a location in a file system, such as C:/Windows/System32 or /usr/bin.

To create a Path we can use the java.nio.Paths.get(String first, String... more) methods. Below you can see how to create a Path by passing only the first string and by passing a first string plus some varargs string.

package org.kodejava.io;

import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;

public class PathCreate {
    public static void main(String[] args) {
        // Create a Path that represents Windows installation location.
        Path windows = Paths.get("C:/Windows");

        // Check to see if the path represent a directory.
        if (Files.isDirectory(windows)) {
            // do something
        }

        // Create a Path that represent Windows programs installation location.
        Path programFiles = Paths.get("C:/Program Files");
        Files.isDirectory(programFiles);

        // Create a Path that represent the notepad.exe program
        Path notepad = Paths.get("C:/Windows", "System32", "notepad.exe");

        // Check to see if the path represent an executable file.
        if (Files.isExecutable(notepad)) {
            // do something
        }
    }
}

How do I use the DosFileAttributes class?

By Wayan in Core API, IO 8 Comments

This example show you how to use the DosFileAttributes class to get file attribute that support DOS file system. This class extends the BasicFileAttributes class. Using the DosFileAttributes class we can read file attributes using isArchive(), isHidden(), isReadOnly() and isSystem() methods.

Let’s see the code snippet below:

package org.kodejava.io;

import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.nio.file.attribute.DosFileAttributes;

public class DosFileAttributeExample {
    public static void main(String[] args) throws Exception {
        String path = "D:/resources/data.txt";

        Path file = Paths.get(path);
        DosFileAttributes attr = Files.readAttributes(file, DosFileAttributes.class);

        System.out.println("isArchive()  = " + attr.isArchive());
        System.out.println("isHidden()   = " + attr.isHidden());
        System.out.println("isReadOnly() = " + attr.isReadOnly());
        System.out.println("isSystem()   = " + attr.isSystem());
    }
}

The output of the code snippet:

isArchive()  = true
isHidden()   = false
isReadOnly() = false
isSystem()   = false

How do I write a text file in JDK 7?

By Wayan in Core API, IO 0 Comment

In JDK 7 we can write all lines from a List of String into a file using the Files.write() method. We need to provide the Path of the file we want to write to, the List of strings and the charsets. Each line is a char sequence and is written to the file in sequence with each line terminated by the platform’s line separator.

Let’s see the code snippet below:

package org.kodejava.io;

import java.nio.charset.StandardCharsets;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.ArrayList;
import java.util.List;

public class WriteTextFile {
    public static void main(String[] args) {
        Path file = Paths.get("D:/resources/data.txt");

        List<String> lines = new ArrayList<>();
        lines.add("Lorem Ipsum is simply dummy text of the printing ");
        lines.add("and typesetting industry. Lorem Ipsum has been the ");
        lines.add("industry's standard dummy text ever since the 1500s, ");
        lines.add("when an unknown printer took a galley of type and ");
        lines.add("scrambled it to make a type specimen book.");

        try {
            // Write lines of text to a file.
            Files.write(file, lines, StandardCharsets.UTF_8);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

This code snippet will create a file called data.txt under the resources folder. Please make sure that this folder is existed before you tried to run the code.

How do I read all lines from a file?

By Wayan in Core API, IO 0 Comment

The java.nio.file.Files.readAllLines() method read all lines from a file. This method ensures that the file is closed when all bytes have been read or an I/O error, or other runtime exception, is thrown. Bytes from the file are decoded into characters using the specified charset.

Note that this method is intended for simple cases where it is convenient to read all lines in a single operation. It is not intended for reading in large files. This method is available since Java 7.

package org.kodejava.io;

import java.net.URI;
import java.nio.charset.Charset;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.List;
import java.util.Objects;

public class ReadFileAsListDemo {
    public static void main(String[] args) {
        ReadFileAsListDemo demo = new ReadFileAsListDemo();
        demo.readFileAsList();
    }

    private void readFileAsList() {
        String fileName = "/data.txt";

        try {
            URI uri = Objects.requireNonNull(this.getClass().getResource(fileName)).toURI();
            List<String> lines = Files.readAllLines(Paths.get(uri),
                    Charset.defaultCharset());

            for (String line : lines) {
                System.out.println(line);
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}