How do I do multipart upload using HttpClient?

This example demonstrates how to do multipart upload using the Apache HttpClient library. In this example we upload a single file. We start by creating an object of the file to be uploaded. The FileBody represent the binary body part of the file.

Next, prepare the HttpEntity object by create an instance of MultipartEntityBuilder. Add parts to this object, in this case we add the fileBody. We can add multiple part to this object as the name says. It can be string, file, etc. as we do in a normal web form.

The build() method of the builder object finalize the entity creation and return us the HttpEntity object. To send / upload to server we create an HttpPost request and set the entity to be posted. Finally, the execute() method of the HttpClient object send the multipart object to server.

package org.kodejava.apache.http;

import org.apache.http.HttpEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.ContentType;
import org.apache.http.entity.mime.HttpMultipartMode;
import org.apache.http.entity.mime.MultipartEntityBuilder;
import org.apache.http.entity.mime.content.FileBody;
import org.apache.http.impl.client.CloseableHttpClient;
import org.apache.http.impl.client.HttpClientBuilder;


public class HttpPostMultipartExample {
    public static void main(String[] args) {
        try (CloseableHttpClient client = HttpClientBuilder.create().build()) {
            File file = new File("");
            FileBody fileBody = new FileBody(file, ContentType.DEFAULT_BINARY);

            MultipartEntityBuilder builder = MultipartEntityBuilder.create();
            builder.addPart("file", fileBody);
            HttpEntity entity =;

            HttpPost request = new HttpPost("http://localhost:8080/upload");
        } catch (IOException e) {

To receive the file on the server you can take a look at the servlet code in the following example: How do I create a web based file upload?.

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