How do I use the Map.forEach() default method?

By Wayan in Java 8, Util Package 0 Comment

The forEach() method in the Map interface in Java 8, allows you to iterate over each entry in the map, allowing you to use each key-value pair in some way.

Here’s a basic usage of the forEach() method:

package org.kodejava.util;

import java.util.HashMap;
import java.util.Map;

public class MapForEachExample {
    public static void main(String[] args) {
        Map<String, Integer> map = new HashMap<>();
        map.put("Apple", 10);
        map.put("Orange", 20);
        map.put("Banana", 30);

        // Use the forEach method. Here, each key-value pair is printed.
        map.forEach((key, value) -> System.out.println("Key: " + key + ", Value: " + value));
    }
}

Output:

Key: Apple, Value: 10
Key: Orange, Value: 20
Key: Banana, Value: 30

In this example, a HashMap is created and populated with some data. The forEach method is then called on this map, with a lambda expression that accepts a key and a value, then prints them. The key and value parameters represent the current key-value pair the forEach method is handling. In this lambda expression, they are printed to the console.

This operation is applied to each entry in the map, hence the name forEach.

Using the forEach method with lambda expressions has several benefits:

  1. Improved Readability: Traditional iteration requires creating an iterator, a while or for loop, and handling each element. With forEach and lambdas, you can express what you want to do with each element clearly and concisely, making the code easier to read and understand
  2. Concurrency Safety: The forEach method is inherently safer to use in concurrent environments. You don’t need to worry about ConcurrentModificationException errors which you might get while using an Iterator and modifying the collection concurrently.
  3. Less Boilerplate Code: The forEach function in combination with a lambda function provides a way to iterate over a collection with fewer lines of code compared to using iterators
  4. Functional Programming: Lambda expressions and functional interfaces pave the way towards functional programming in Java, which allows for more expressive ways to manipulate collections.

Remember, although forEach can make your code more concise, it does not necessarily make it faster.

How do I use the List.sort() method?

By Wayan in Java 8, Util Package 0 Comment

The List.sort() method was introduced in Java 8. This method sorts the elements of the list on the basis of the given Comparator. If no comparator is provided, it will use the natural ordering of the elements (only if the elements are Comparable).

Let’s take a look at an example where we sort a list of integers in ascending order:

package org.kodejava.util;

import java.util.ArrayList;
import java.util.List;

public class ListSortExample {
    public static void main(String[] args) {
        List<Integer> numbers = new ArrayList<>();
        numbers.add(3);
        numbers.add(1);
        numbers.add(4);
        numbers.add(1);
        numbers.add(5);

        // Use sort() to sort the numbers in ascending order
        numbers.sort(null);

        System.out.println(numbers); 
    }
}

Outputs:

[1, 1, 3, 4, 5]

You can also pass a Comparator to List.sort(). Here’s an example where we sort a list of strings by their length:

package org.kodejava.util;

import java.util.ArrayList;
import java.util.Comparator;
import java.util.List;

public class ListSortOtherExample {
    public static void main(String[] args) {
        List<String> words = new ArrayList<>();
        words.add("rat");
        words.add("elephant");
        words.add("cat");
        words.add("mouse");

        // Comparator for comparing string lengths
        Comparator<String> lengthComparator = (s1, s2) -> s1.length() - s2.length();

        // Use sort() to sort the words by their length
        words.sort(lengthComparator);

        System.out.println(words);
    }
}

Outputs:

[rat, cat, mouse, elephant]

In this case, the Comparator is a lambda expression that computes the difference in length between two strings. The List.sort() method uses this Comparator to determine the ordering of the strings in the list.

How do I use List.replaceAll() method?

By Wayan in Java 8, Util Package 0 Comment

The List.replaceAll() method was introduced in Java 8. This method replaces each element of the list with the result of applying the operator to that element. The operator or function you pass to replaceAll() should be a UnaryOperator.

Here is a simple example:

package org.kodejava.util;

import java.util.ArrayList;
import java.util.List;
import java.util.function.UnaryOperator;

public class ListReplaceAllExample {
    public static void main(String[] args) {
        List<Integer> numbers = new ArrayList<>();
        numbers.add(1);
        numbers.add(2);
        numbers.add(3);
        numbers.add(4);
        numbers.add(5);

        // Define an UnaryOperator to square each number
        UnaryOperator<Integer> square = n -> n * n;

        // Use replaceAll() method to square each number in the list
        numbers.replaceAll(square);

        System.out.println(numbers);
    }
}

Outputs:

[1, 4, 9, 16, 25]

In this example, the UnaryOperator square squares each element. The List.replaceAll() method applies this operator to all elements in the list.

Note that replaceAll() modifies the original list and does not return a new list. Please also be aware that this operation is in-place and hence modifies the original List. If you want to keep the original List unchanged, create a new List and add elements to it after applying the function.

The primary purpose of the List.replaceAll() method in Java is to perform an in-place transformation of all elements within a list based on a given unary function or operation.

A Unary function or operation is one that takes a single input and produces a result. In the context of replaceAll(), the unary operation is typically provided as a lambda expression or method reference which is applied to each element in the list in turn.

If successful, replaceAll() modifies the list such that each original element has been replaced by the result of applying the provided unary operation to that element. This operation is performed on the original list, and no new list is created, making it an efficient option for transforming large lists.

Here is an example which doubles each integer in a list:

package org.kodejava.util;

import java.util.ArrayList;
import java.util.List;

public class ListReplaceAllSecondExample {
    public static void main(String[] args) {
        List<Integer> ints = new ArrayList<>();

        ints.add(1);
        ints.add(2);
        ints.add(3);

        // Double every integer in the List
        ints.replaceAll(n -> n * 2);

        System.out.println(ints); 
    }
}

Outputs:

[2, 4, 6]

In conclusion, List.replaceAll() provides a convenient and efficient way to modify all elements in a list according to a specified operation or function. It’s especially useful when using the Streams API and functional programming techniques introduced in Java 8.

How do I use Collection.removeIf() method?

By Wayan in Java 8, Util Package 0 Comment

The Collection.removeIf() method was introduced in Java 8, and it allows for the removal of items from a collection using a condition defined in a lambda expression.

The primary purpose of the Collection.removeIf() method in Java is to filter out elements from a collection based on a certain condition or predicate. It’s a more efficient and concise way of performing this type of operation than traditional for or iterator-based loops.

The method iterates over each element in the collection and checks whether it satisfies the condition described by the given Predicate. If the Predicate returns true for a particular element, removeIf() removes that element from the collection.

Here’s a simple example:

package org.kodejava.util;

import java.util.ArrayList;
import java.util.List;

public class CollectionRemoveIfExample {
    public static void main(String[] args) {
        List<Integer> numbers = new ArrayList<>();
        numbers.add(1);
        numbers.add(2);
        numbers.add(3);
        numbers.add(4);
        numbers.add(5);

        // Use removeIf method to remove all numbers greater than 2
        numbers.removeIf(n -> n > 2);

        System.out.println(numbers); // Outputs: [1, 2]
    }
}

In this example, n -> n > 2 is a lambda expression that defines a Predicate, which returns true for all numbers greater than 2. The removeIf() method uses this Predicate to determine which elements to remove.

Please be aware that not all Collection implementations support the removeIf() method. For example, if you try to use it with an unmodifiable collection (like the ones returned by Collections.unmodifiableList()), it will throw an UnsupportedOperationException.

As removeIf() is a default method, it’s provided with a default implementation, and it’s available for use with any classes that implement the Collection interface (like ArrayList, HashSet, etc.) without requiring those classes to provide their own implementation.

However, classes can still override this method with their own optimized version if necessary. Here’s another example of removeIf() method:

package org.kodejava.util;

import java.util.ArrayList;
import java.util.List;

public class CollectionRemoveIfSecond {
    public static void main(String[] args) {
        List<String> names = new ArrayList<>();
        names.add("Alice");
        names.add("Bob");
        names.add("Charlie");
        names.add("David");
        names.add("Rosa");

        // Remove names that start with 'B'
        names.removeIf(name -> name.startsWith("B"));

        System.out.println(names); // Outputs: [Alice, Charlie, David, Rosa]
    }
}

Remember, it’s a bulk operation that can lead to a ConcurrentModificationException if the collection is modified while the operation is running (for example, removing an element from a collection while iterating over it with removeIf()), except if the collection is a Concurrent Collection.

In conclusion, the Collection.removeIf() default method provides a unified, efficient, and convenient way to remove items from a collection based on certain conditions.

What is the purpose of String.strip() method of Java 11?

By Wayan in Lang Package 0 Comment

The purpose of the String.strip() method in Java 11 is to remove whitespaces from both the beginning and end of a string. This is very similar to the String.trim() method available in earlier versions of Java, but there is a key difference between them.

Here’s the difference:

  • String.strip(): Introduced in Java 11, strip() uses the unicode definition of whitespace. It removes not only space characters but also all other types of unicode-defined spaces, such as the thin space \u2009, etc.
  • String.trim(): Available from Java 1.0, trim() is more limited. It considers a whitespace to be any character whose ASCII value is less than or equal to 32 (a space, tab, newline, and a few other control characters).

Here are examples of how they work:

package org.kodejava.lang;

public class StringStripExample {
    public static void main(String[] args) {
        // String.strip()
        String first = " \u2009Hello  ";
        System.out.println(first.strip()); // Outputs "Hello"

        // String.trim()
        String second = " \u2009Hello  ";
        System.out.println(second.trim()); // Outputs "\u2009Hello"
    }
}

Output:

Hello
 Hello

Thus, strip() method is more comprehensive in removing different types of whitespace defined in Unicode, while trim() only removes ASCII control characters and spaces.

There are also String.stripLeading() and String.stripTrailing() methods that were introduced in Java 11, and they are similar to the strip() method, but they only remove the whitespace characters from either the beginning or the end of the string, respectively.

Here is what they do:

  • String.stripLeading(): This method removes any leading whitespace from the string. “Leading” in this context means any whitespace characters at the beginning of the string.
  • String.stripTrailing(): This method removes any trailing whitespace from the string. “Trailing” in this context means any whitespace characters at the end of the string.

Both stripLeading() and stripTrailing() use the Unicode definition of whitespace, the same as strip() method.

Here are examples of how they work:

package org.kodejava.lang;

public class StringStripLeadingTrailingExample {
    public static void main(String[] args) {
        // Strip leading whitespace
        String first = " \u2009Hello World  ";
        System.out.println(first.stripLeading());  // Outputs "Hello World  "

        // Strip trailing whitespace
        String second = " \u2009Hello World  ";
        System.out.println(second.stripTrailing()); // Outputs " \u2009Hello World"
    }
}

Output:

Hello World  
  Hello World

As demonstrated, stripLeading() removed the whitespace characters from the front of the string, and stripTrailing() removed the whitespace characters from the end of the string.

While \u00A0 is technically a type of whitespace (specifically, a non-breaking space or NBSP), it isn’t considered as such by the strip(), stripLeading(), and stripTrailing() methods, which follow the Character.isWhitespace(char) method’s definition of what constitutes a whitespace character.

According to the Java documentation, the Character.isWhitespace(char) method, which the strip() methods use, considers the following characters as whitespace:

  • ‘\t’ U+0009 HORIZONTAL TABULATION
  • ‘\n’ U+000A LINE FEED
  • ‘\u000B’ U+000B VERTICAL TABULATION
  • ‘\f’ U+000C FORM FEED
  • ‘\r’ U+000D CARRIAGE RETURN
  • ‘\u001C’ U+001C FILE SEPARATOR
  • ‘\u001D’ U+001D GROUP SEPARATOR
  • ‘\u001E’ U+001E RECORD SEPARATOR
  • ‘\u001F’ U+001F UNIT SEPARATOR
  • SPACE_SEPARATOR category types

The \u2009 (thin space) and \u0020 (space) are part of SPACE_SEPARATOR category according to Unicode standard and will be correctly stripped.

The \u00A0 (non-breaking space) is actually part of a different category called the NO-BREAK_SPACE and is not considered whitespace by Character.isWhitespace(char), so it won’t be stripped.