How do I use reluctant quantifier regex?

By Wayan in Regex 2 Comments

The reluctant quantifiers start the matcher at the beginning of the input string, then reluctantly eat one character at a time looking for a match. The last thing they try is the entire input string.

package org.kodejava.regex;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class ReluctantQuantifierDemo {
    public static void main(String[] args) {
        String[] expressions =
                {"x??", "x*?", "x+?", "x{2}?", "x{2,}?", "x{2,5}?"};
        String input = "xxxxxxx";

        for (String expression : expressions) {
            Pattern pattern = Pattern.compile(expression);
            Matcher matcher = pattern.matcher(input);

            // Find every match and print it
            System.out.println("------------------------------");
            System.out.format("regex:  %s %n", expression);
            while (matcher.find()) {
                System.out.format("Text \"%s\" found at %d to %d%n",
                        matcher.group(), matcher.start(),
                        matcher.end());
            }
        }
    }
}

The results of the snippet shown below:

regex:  x?? 
Text "" found at 0 to 0
Text "" found at 1 to 1
Text "" found at 2 to 2
Text "" found at 3 to 3
Text "" found at 4 to 4
Text "" found at 5 to 5
Text "" found at 6 to 6
Text "" found at 7 to 7
------------------------------
regex:  x*? 
Text "" found at 0 to 0
Text "" found at 1 to 1
Text "" found at 2 to 2
Text "" found at 3 to 3
Text "" found at 4 to 4
Text "" found at 5 to 5
Text "" found at 6 to 6
Text "" found at 7 to 7
------------------------------
regex:  x+? 
Text "x" found at 0 to 1
Text "x" found at 1 to 2
Text "x" found at 2 to 3
Text "x" found at 3 to 4
Text "x" found at 4 to 5
Text "x" found at 5 to 6
Text "x" found at 6 to 7
------------------------------
regex:  x{2}? 
Text "xx" found at 0 to 2
Text "xx" found at 2 to 4
Text "xx" found at 4 to 6
------------------------------
regex:  x{2,}? 
Text "xx" found at 0 to 2
Text "xx" found at 2 to 4
Text "xx" found at 4 to 6
------------------------------
regex:  x{2,5}? 
Text "xx" found at 0 to 2
Text "xx" found at 2 to 4
Text "xx" found at 4 to 6

How do I use possessive quantifier regex?

By Wayan in Regex 0 Comment

The possessive quantifiers always eat the entire input string, trying once (and only once) for a match. Unlike the greedy quantifiers, possessive quantifiers never back off, even if doing so would allow the overall match to succeed.

package org.kodejava.regex;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class PossessiveQuantifierDemo {
    public static void main(String[] args) {
        String[] regexs = {
                "x?+",
                "x*+",
                "x++",
                "x{2}+",
                "x{2,}+",
                "x{2,5}+"
        };
        String input = "xxxxxxx";

        for (String r : regexs) {
            Pattern pattern = Pattern.compile(r);
            Matcher matcher = pattern.matcher(input);

            // Find every match and print it
            System.out.format("Regex:  %s%n", r);
            while (matcher.find()) {
                System.out.format("Text \"%s\" found at %d to %d.%n",
                        matcher.group(), matcher.start(),
                        matcher.end());
            }
            System.out.println("------------------------------");
        }
    }
}

The output of the code snippet above are:

Regex:  x?+
Text "x" found at 0 to 1.
Text "x" found at 1 to 2.
Text "x" found at 2 to 3.
Text "x" found at 3 to 4.
Text "x" found at 4 to 5.
Text "x" found at 5 to 6.
Text "x" found at 6 to 7.
Text "" found at 7 to 7.
------------------------------
Regex:  x*+
Text "xxxxxxx" found at 0 to 7.
Text "" found at 7 to 7.
------------------------------
Regex:  x++
Text "xxxxxxx" found at 0 to 7.
------------------------------
Regex:  x{2}+
Text "xx" found at 0 to 2.
Text "xx" found at 2 to 4.
Text "xx" found at 4 to 6.
------------------------------
Regex:  x{2,}+
Text "xxxxxxx" found at 0 to 7.
------------------------------
Regex:  x{2,5}+
Text "xxxxx" found at 0 to 5.
Text "xx" found at 5 to 7.
------------------------------

How do I write embedded flag expression?

By Wayan in Regex 0 Comment

It’s also possible to enable various flags using embedded flag expressions. Embedded flag expressions are an alternative to the two-argument version of compile, and are specified in the regular expression itself. The example below is use (?i) flag expression to enable case-insensitive matching.

Another flag expressions are listed below:

  • (?x), equivalent with Pattern.COMMENTS
  • (?m), equivalent with Pattern.MULTILINE
  • (?s), equivalent with Pattern.DOTTAL
  • (?u), equivalent with Pattern.UNICODE_CASE
  • (?d), equivalent with Pattern.UNIX_LINES
package org.kodejava.regex;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class EmbeddedFlagDemo {
    public static void main(String[] args) {
        // Define regex which starting with (?i) to enable
        // case-insensitive matching
        String regex = "(?i)the";
        String text = "The quick brown fox jumps over the lazy dog";

        // Obtain the required matcher
        Pattern pattern = Pattern.compile(regex);
        Matcher matcher = pattern.matcher(text);

        // Find every match and print it
        while (matcher.find()) {
            System.out.format("Text \"%s\" found at %d to %d.%n",
                    matcher.group(), matcher.start(),
                    matcher.end());
        }
    }
}

The result of the program is:

Text "The" found at 0 to 3.
Text "the" found at 31 to 34.

How do I pause the current thread?

By Wayan in Core API, Lang Package 0 Comment

You can pause a current thread for a number of milliseconds by using the sleep() method of the Thread class. While the current thread is sleeping, it will allow other threads to execute.

package org.kodejava.lang;

public class ThreadSleepDemo implements Runnable {
    public static void main(String[] args) {
        Thread thread = new Thread(new ThreadSleepDemo());
        thread.start();
    }

    // The run() method will be invoked when the thread is started.
    public void run() {
        System.out.println("Start..");
        try {
            // Wait for 10 seconds
            Thread.sleep(10000);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println("Finish...");
    }
}

How do I start a thread execution?

By Wayan in Core API, Lang Package 0 Comment

To make a thread begin its execution, call the start() method on a Thread or Runnable instance. Then the Java Virtual Machine will calls the run method of this thread.

The snippet below is showing how to create a thread by implementing the Runnable interface.

package org.kodejava.lang;

public class ThreadRun implements Runnable {

    public static void main(String[] args) {
        // Instantiate ThreadRun
        ThreadRun runner = new ThreadRun();

        // Create instance of Thread and passing ThreadRun object
        // as argument.
        Thread thread = new Thread(runner);

        // By passing Runnable object, it tells the
        // thread to use run() of Runnable object.
        thread.start();
    }

    public void run() {
        System.out.println("Running..");
    }
}

The snippet below is showing how to create a thread by extending the Thread class.

package org.kodejava.lang;

public class ThreadStart extends Thread {

    public static void main(String[] args) {
        ThreadStart thread = new ThreadStart();

        // Start this thread
        thread.start();
    }

    /**
     * The run() method will be invoked when the thread is started.
     */
    @Override
    public void run() {
        System.out.println("Running..");
    }
}