How do I remove trailing white space from a string?

The trim() method of a String class removes both leading and trailing white space from a string. In this example we use a regular expression to remove only the trailing white spaces from a string.

package org.kodejava.lang;

public class TrailingSpace {
    public static void main(String[] args) {
        String text = "     tattarrattat     ";
        System.out.println("Original      = " + text);
        System.out.println("text.length() = " + text.length());

        // Using a regular expression to remove only the trailing white space in
        // a string
        text = text.replaceAll("\\s+$", "");
        System.out.println("Result        = " + text);
        System.out.println("text.length() = " + text.length());
    }
}
Original      =      tattarrattat     
text.length() = 22
Result        =      tattarrattat
text.length() = 17

How do I remove leading white space from a string?

The trim() method of a String class removes both leading and trailing white space from a string. In this example we use a regular expression to remove only the leading white spaces from a string.

package org.kodejava.lang;

public class LeadingSpace {
    public static void main(String[] args) {
        String text = "     tattarrattat     ";
        System.out.println("Original      = " + text);
        System.out.println("text.length() = " + text.length());

        // Using regular expression to remove only the leading white
        // space in string
        text = text.replaceAll("^\\s+", "");
        System.out.println("Result        = " + text);
        System.out.println("text.length() = " + text.length());
    }
}
Original      =      tattarrattat     
text.length() = 22
Result        = tattarrattat     
text.length() = 17

How do I create a method that accept varargs in Java?

Varargs (variable arguments) is a new feature in Java 1.5 which allows us to pass multiple values in a single variable name when calling a method. Of course, it can be done easily using array but the varargs add another power to the language.

The varargs can be created by using three periods (...) after the parameter type. If a method accept others parameter than the varargs, the varargs parameter should be the last parameter to the method. And please be aware that overloading a varargs method can make harder to figure out which method is called in the code.

package org.kodejava.lang;

import java.util.Arrays;

public class VarArgsExample {
    public static void main(String[] args) {
        VarArgsExample e = new VarArgsExample();
        e.printParams(1, 2, 3);
        e.printParams(10, 20, 30, 40, 50);
        e.printParams(100, 200, 300, 400, 500);
    }

    public void printParams(int... numbers) {
        System.out.println(Arrays.toString(numbers));
    }
}

Running the code snippet give you the following output:

[1, 2, 3]
[10, 20, 30, 40, 50]
[100, 200, 300, 400, 500]

How do I know the class of an object?

For instance, you have a collection of objects in an List object, and you want to do some logic based on the object’s class. This can easily be done using the instanceof operator. The operator returns true if an object is an instance of a specified class, if not it will return false.

The instanceof operator is most likely used when implementing an equals(Object o) method of an object to check if the compared object is from the same class.

package org.kodejava.lang;

import java.util.ArrayList;
import java.util.List;

public class InstanceOfExample {
    public static void main(String[] args) {
        Person person = new Person("John");
        Animal animal = new Animal("Highland");
        Thing thing = new Thing("Red");
        String text = "hello";
        Integer number = 1000;

        List<Object> list = new ArrayList<>();
        list.add(person);
        list.add(animal);
        list.add(thing);
        list.add(text);
        list.add(number);

        for (Object o : list) {
            if (o instanceof Person) {
                System.out.println("My name is " + ((Person) o).getName());
            } else if (o instanceof Animal) {
                System.out.println("I live in " + ((Animal) o).getHabitat());
            } else if (o instanceof Thing) {
                System.out.println("My color is " + ((Thing) o).getColor());
            } else if (o instanceof String) {
                System.out.println("My text is " + o.toString());
            } else if (o instanceof Integer) {
                System.out.println("My value is " + ((Integer) o));
            }
        }
    }
}

class Person {
    private final String name;

    public Person(String name) {
        this.name = name;
    }

    public String getName() {
        return name;
    }
}

class Animal {
    private final String habitat;

    public Animal(String habitat) {
        this.habitat = habitat;
    }

    public String getHabitat() {
        return habitat;
    }
}

class Thing {
    private final String color;

    public Thing(String color) {
        this.color = color;
    }

    public String getColor() {
        return color;
    }
}

The result of the code snippet above:

My name is John
I live in Highland
My color is Red
My text is hello
My value is 1000

How do I replace characters in string?

package org.kodejava.lang;

public class StringReplace {
    public static void main(String[] args) {
        String text = "The quick brown fox jumps over the lazy dog";
        System.out.println("Before: " + text);

        // The replace method replace all occurrences of character
        // 'o' with 'u' and returns a new string object.
        text = text.replace('o', 'u');
        System.out.println("After : " + text);
    }
}

The result of the code snippet:

Before: The quick brown fox jumps over the lazy dog
After : The quick bruwn fux jumps uver the lazy dug